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t^2= 5^2 + 12^2
t^2 = 25 + 144
t^2 = 169
t = 13 cm
luasnya = 4 x 1/2 x a x t
= 2 x 10 x 13
= 260 cm^2
#luas balok
= 2(pl + pt + lt)
= 2[(14 x 12) + (14 x 10) + (12 x 10)]
= 2(168 + 140 + 120)
= 2(428)
= 856 cm^2
#luas alas limas
= s x s
= 10 x 10
= 100 cm^2
#luas permukaan total
= luas segitiga tegak limas + luas balok - luas alas limas
= 260 + 856 - 100
= 1016 cm^2 (B)
NOTE :
itu dikurangi karena luas alas limas ada diatas balok..