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y-y1/y2-y1 = x-x1/x2-x1
y-2/-1-2 = x-4/0-4
y-2/-3 = x-4/-4
-4y+8 = -3x+12
3x-4y-4 = 0
m = -a/b = -3/-4 = 3/4
m1 × m2 = -1
3/4 × m2 = -1
m2 = -4/3
y-2 = -4/3(x-4)
y-2 = -4/3x+16/3
4/3x+y-22/3 = 0 (3)
4x+3y-22 = 0 (c)
garis l melalui titik (0, -1) dan (4, 2)
m = y2-y1 : x2-x1
= 2-(-1) : 4-0
= 2+1 : 4
= 3/4
karena garis k tegak lurus dengan l maka
ml × mk = -1
3/4 × mk = -1
mk = -1 : 3/4
mk = -4/3
setelah tau mk, hitung persamaan dengan memasukkan titik (4,2) pada rumus persamaan
y-y1 = m (x-x1)
y-2 = -4/3 (x-4)
y-2 = -4/3x + 16/3
(karena masih ada pecahan, maka semua dikali 3 agar pecahan hilang)
y-2 = -4/3x + 16/3 (×3)
3y - 6 = -4x + 16
3y + 4x - 6 - 16 = 0
4x + 3y - 22 = 0 (D)
mohon maaf kalau keliru. semoga bermanfaat