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Verified answer
KALORm = 500 gr
te = -15 °C
ce = 0,6 kal/(gr °C)
L = 80 kal/gr
ca = 1 kal/(gr °C)
U = 540 kal/gr
Q = ___?
• suhu es naik
Q₁ = m ce ∆t
Q₁ = 500 • 0,6 • (0 - (-15))
Q₁ = 4500 kal
• es melebur menjadi air
Q₂ = m L
Q₂ = 500 • 80
Q₂ = 40000 kal
• suhu air naik
Q₃ = m ca ∆ta
Q₃ = 500 • 1 • (100 - 0)
Q₃ = 50000 kal
• air menguap
Q₄ = m U
Q₄ = 500 • 540
Q₄ = 270000 kal
Kalor yang dibutuhkan untuk mengubah es -15 °C menjadi uap seluruhnya
Q = Q₁ + Q₂ + Q₃ + Q₄
Q = 4500 + 40000 + 50000 + 270000
Q = 364500 kal = 364,5 kkal ✓