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(x + 1)(x + 3) ===> pembuat nol fungsi x = -1 v x = -3
f(x) = (x² + 4x + 3).H(x) + 2x + 17
f(x) = (x + 1)(x + 3).H(x) + 2x + 17
f(-1) = (-1 + 1)(x + 3)H(x) + 2.(-1) + 17
f(-1) = 15
f(-3) = 11
f(x) = (x² - 4).H(x) + 3x - 5
f(x) = (x - 2)(x + 2).H(x) + 3x - 5
f(2) = 1
f(-2) = -11
f(x) = (x² + x - 6).H(x) + ax + b
f(x) = (x - 2)(x + 3).H(x) + ax + b
f(2) = 1
2a + b = 1.......1
f(-3) = 11
-3a + b = 11........2
dari 1 dan 2 didapat a = -2, b = 5
sehingga S(x) = ax + b = -2x + 5