Question

tolong ya Kaka besok harus di kumpulkan ini ada soal 2 - 5 tolong di kerjakan dengan benar no asal asalan terimakasih ​

Answer 1

Jawab:

Penjelasan dengan langkah-langkah:

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2.

Diketahui:

=> Diameter lingkaran 30cm

Ditanya:

=> Keliling lingkaran ?

Jawab:

[tex]= > Keliling = \pi \times Diameter (gunakan \pi =3.14)\\= > Keliling = 3.14 \times 30cm\\= > Keliling = 94.2cm[/tex]

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3.

Diketahui:

=> Keliling lingkaran 88cm

Ditanya:

=> Jari-jari lingkaran ?

Jawab:

[tex]= > Keliling = 2\pi r\\= > 88 = 2\times\frac{22}{7} \times r\\= > r = \frac{88}{2\times\frac{22}{7} }\\= > r = \frac{44}{\frac{22}{7} }\\= > r = \frac{44\times7}{22}\\= > r =2\times7\\= > r= 14[/tex]

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4.

Diketahui:

Jari - jari lingkaran P ([tex]r_{P}[/tex]) = 3cm

Jari - jari lingkaran Q ([tex]r_{Q}[/tex]) = 5cm

Ditanya:

Perbandingan keliling lingkaran P ([tex]k_{P}[/tex]) dan keliling lingkaran Q ([tex]k_{Q}[/tex])?

Jawab:

[tex]= > k_{P} :k_{Q} = 2\pi r_{P} : 2\pi r_{Q}\\= > \frac{k_{P}}{k_{Q}} = \frac{2\pi r_{P}}{2\pi r_{Q}} (coret\ 2\pi ) \\= > \frac{k_{P}}{k_{Q}} = \frac{ r_{P}}{r_{Q}} \\= > \frac{k_{P}}{k_{Q}} = \frac{3}{5}\\= > Perbandingan\ k_{P}\ terhadap\ k_{Q}\ adalah\ \frac{3}{5} (3\ banding\ 5)[/tex]

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5.

Diketahui:

=> roda jari-jari 14cm

=> panjang lintasan roda 792cm

Ditanya:

Berapa kali berputar ?

Jawab:

Jumlah putaran roda/lingkaran :

[tex]= > \frac{Panjang\ lintasan}{Keliling\ roda}\\\\\\= > \frac{792}{2\pi r}cm\\\\\\= > \frac{792}{2\times\frac{22}{7} \times 14}cm\\\\= > \frac{792}{2\times 22 \times 2}\\\\= > \frac{792}{88}\\\\= > 9\ putaran[/tex]