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R = √(21² + 20²) = √(441 + 400) =
√(841) = 29 ✔
p = \binom{12}{ - 2} \\ q = \binom{9}{22}
p+q = (12+9)+(-2+22)
R²=21²+20²
R²=441+400
R=√841
R=29
maka besar resultan vektor tersebut adalah 29