Question

Tolong ya dijawab no 1 dan 2 buat besok dengan canya nya juga ya plisss

Answer 1

1. a. (2x + 1)/(2x - 1) + (2x - 1)/(2x + 1) **jadikan penyebutnya (2x + 1)(2x - 1)**
= (2x + 1)(2x + 1)/(2x + 1)(2x - 1) + (2x - 1)(2x - 1)/(2x + 1)(2x - 1)
= [(2x + 1)² + (2x - 1)²]/(2x + 1)(2x - 1) 

b. 2/(a² + 4a + 3) - 1/(a + 1)= 2/(a + 3)(a + 1) - 1/(a + 1) **jadikan penyebutnya (a + 3)(a + 1)
= 2/(a + 3)(a + 1) - (a + 3)/(a + 3)(a + 1)
= (2 - a - 3)/(a + 3)(a + 1)
= (-a - 1)/(a + 3)(a + 1)
= -(a + 1)/(a + 3)(a + 1)
= -1/(a + 3)

c. 2/(z² - 1) + 1/(z + 1)
= 2/(z + 1)(z - 1) + 1/(z + 1) **jadikan penyebutnya (z + 1)(z - 1)**
= 2/(z + 1)(z - 1) + (z - 1)/(z + 1)(z - 1)
= (2 + z - 1)/(z + 1)(z - 1)
= (1 + z)/(z + 1)(z - 1)
= 1/(z - 1)

d. 2/(a + 2b) + 1/(a² + 4ab + 4b²)
= 2/(a + 2b) + 1/(a + 2b)² **jadikan penyebutnya (a + 2b)²**
= 2(a + 2b)/(a + 2b)² + 1/(a + 2b)²
= (2a + 4b + 1)/(a + 2b)²

e. 3/(x² - 9) - 1/(x + 3)
= 3/(x + 3)(x - 3) - 1/(x + 3) **jadikan penyebutnya (x + 3)(x - 3) **
= 3/(x + 3)(x - 3) - (x - 3)/(x + 3)(x - 3) 
= (3 - x + 3)/(x + 3)(x - 3) 
= (6 - x)/(x + 3)(x - 3) 

2. a. (t² - 3t - 10)/(2t + 2) x (t + 1)/(t² - 5t)
= (t - 5)(t + 2)/2(t + 1) x (t + 1)/t(t - 5)
= (t + 2)/2t

b. (p² - 2p)/(p² + 4p + 3) x (p² + p)/(p - 2)
= p(p - 2)/(p + 3)(p + 1) x p(p + 1)/(p - 2)
= p²/(p + 3)

c. (n² + n - 12)/(m² - 2m + 1) x (m - 1)/(n - 3)
= (n - 3)(n + 4)/(m - 1)² x (m - 1)/(n - 3)
= (n + 4)/(m - 1)

d. (c + 1)/(c² - 5c + 6) x (c - 2)/(4c + 4)
= (c + 1)/(c - 3)(c - 2) x (c - 2)/4(c + 1)
= 1/[4(c - 3)]

e. (a² - 1)/(a + 1) x (a - 1)/(a² - 2a + 1)= (a + 1)(a - 1)/(a + 1) x (a - 1)/(a - 1)²
= (a - 1)/(a - 1)
= 1

Kalau ada yg salah, silakan dikoreksi :)