ImmanuelSinaga
1. karena bilangan pokok sama maka sama sama di coret 4x+1=2x-3 4x-2x=-3-1 2x=-4 x=-4/2=-2 2. kita ubah agar bilangan pokok=3 = bilangan pokok sama sama 3 dicoret (2x+1)/2=2x-4 2x+1=4x-8 4x-2x=1+8 2x=9 x=9/2 3.kita ubah bilangan pokok=3 ∞= ∞= = bil.pokok=3 = -9x+21=1-x =-9x+x=1-21 =-8x=-20 x=-20/-8=5/2 4.ubah jadi bilangan pokok sama sama 7,dicoret x²-6x-16=2x-6 x²-6x-2x-16+6=0 x²-8x-10=0 rumus abc=-b+√(b²-4ac)/2a 8+√(64+40)/2=8+√104/2=4+√26 5.64= 4∧(x+3)=4∧3/x+5 x+3=3/x+5 (x+3)(x+5)=3 x²+15+8x=3 x²+8x+12=0 (x+6)(x+2) x=-6 x=-2 6.2∧(x²+ 3x)=2∧(4x+6) x²+3x=4x+6 x²-x+6=0 (x-3)(x+2)=0 x=3 x=-2
4x+1=2x-3
4x-2x=-3-1
2x=-4
x=-4/2=-2
2. kita ubah agar bilangan pokok=3
bilangan pokok sama sama 3 dicoret
(2x+1)/2=2x-4
2x+1=4x-8
4x-2x=1+8
2x=9
x=9/2
3.kita ubah bilangan pokok=3
∞
∞
= bil.pokok=3
= -9x+21=1-x
=-9x+x=1-21
=-8x=-20
x=-20/-8=5/2
4.ubah jadi
bilangan pokok sama sama 7,dicoret
x²-6x-16=2x-6
x²-6x-2x-16+6=0
x²-8x-10=0
rumus abc=-b+√(b²-4ac)/2a
8+√(64+40)/2=8+√104/2=4+√26
5.64=
4∧(x+3)=4∧3/x+5
x+3=3/x+5
(x+3)(x+5)=3
x²+15+8x=3
x²+8x+12=0
(x+6)(x+2)
x=-6
x=-2
6.2∧(x²+ 3x)=2∧(4x+6)
x²+3x=4x+6
x²-x+6=0
(x-3)(x+2)=0
x=3
x=-2