Question

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bantuin

5.Hitunglah luas selimut tabung di atas!
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Answer 1

Verified answer

4. diameter tabung = 7 dm, maka r = 7/2 dm

Volume tabung:

V = πr²t

[tex]=\sf\frac{22}{7}\cdot\frac{7}{2} \cdot\frac{7}{2} \cdot 8\\\\=11\cdot7\cdot4\\\\=308\:dm^{3}[/tex]

Volume kubus:

V = s³

= 7³

= 343 dm³

Volume gabungan:

V = V tabung + V kubus = 308 + 343 = 651 dm³ = 651 liter

Jadi, volume gabungan bangun ruang tersebut adalah 651 liter.

5. Luas selimut tabung:

L = Keliling lingkaran x t

L = 2πrt

[tex]\sf=2\cdot\frac{22}{7}\cdot14\cdot35\\ \\=2\cdot22\cdot2\cdot35\\\\=3.080\:cm^{3}[/tex]

Jadi, luas selimut tabung tersebut adalah 3.080 cm³.

[tex]\boxed{\sf{shf}}[/tex]

Answer 2

4. V.tabung + V.kubus

V.tabung

V = πr²t

V = 22/7 × (7 ÷ 2)² × 8

V = 22/7 × 3,5 × 3,5 × 8

V = 22 × 0,5 × 3,5 × 8

V = 11 × 3,5 × 8

V = 38,5 × 8

V = 308 dm³

V.kubus

V = r³

V = 7³

V = 7 × 7 × 7

V = 49 × 7

V = 343 dm³

308 + 343 = 651 dm³ = 651 liter

2. Luas selimut

Ls = 2πrt

Ls = 2 × 22/7 × 14 × 35

Ls = 2 × 22 × 2 × 35

Ls = 44 × 2 × 35

Ls = 88 × 35

Ls = 3.080 cm²