Question

tolong solusinya matematika tentang menentukan nilai perbandingan trigonometri untuk sudut khusus terimakasih ​

Answer 1

Jawaban:

a) Sin 30° + Tan 45° = ½ + 1 = 1½

b) Sin 60° + Tan 30° = ½ + √3

c) Cos 60° + Cot 45°

= Cos 60° + 1/ Tan 45°

= ½ + 1/ 1

= ½ + 1

= 1½

d) Tan 30 + Tan 45

= ⅓√3 + 1

e) Tan 30 + Tan 60

= ⅓√3 + √3

= ⅓√3 + 1√3

= ⅓√3 + 3/3√3

= 4/3√3

f) sec 0 + sec 45

=1/cos 0 + 1/ cos 45

= 1/1 + 1/√2/2

= 1 + 2√2

= 1 + 2√2/2

= 1 + √2

g) sec 60 + cosec 30

= 1 / cos 60 + 1/ sin 30

= 1/ ½ + 1/ ½

= 2 + 2

= 4

h) sin 30 x cos 60 + cos 45

= ½ x ½ + √2/2

= ¼ + √2/2

i) sin 60 x cos 60 + sin 30 x cos 30

= √3/2 x ½ + ½ x √3/2

= ½√3/2 + ½√3/2

= √3/4 + √3/4

= 2√3/4

= ½√2

j) Sin 30 x cos 45 x Tan 60

= ½ x √2/2 x √3

= √2/4 x √3

= √6/4