Question

Tolong saya yah yg pintar matematika,mau dikumpulin jam 8 nnti:(:)
sederhanakanlah :
1. 4 log (x+1) + 4 log (x+1)'3
2. 3 log {x'2-4} - 3 log {x+2}

Answer 1

Jika 4 dan 3 nya basis
1. ⁴log (x + 1) + ⁴log (x + 1)³
= ⁴log (x + 1)⁴

2. ³log (x² - 4) - ³log (x + 2)
= ³log (x² - 4)/(x + 2)
= ³log (x - 2)

Answer 2

1.    ⁴log(x+1) + 4 log(x+1)³

=  ⁴log(x+1)⁴
=2.²log(x+1)

2.    ³log(x²-4)-³log(x+2)

        ³log(x²-4)   =³log(x-2)(x+2)
                        =³log(x-2) + ³log(x+2)

³log(x²-4)-³log(x+2)  = ³log(x-2) + ³log(x+2)-³log(x+2)  {mksdny dicoret}
                             =³log(x-2)