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= 12√2
ec²=(12√2)² + 12²
ec=√(288)+144
ec=12√3
Rumus bidang diagonal Kubus = s√2
diketahui rusuk = 12
EC = 12√3
BD = 12√2
AC → BD = r² = √(( EC )² - ( BD )² )
= (12√3 )² - ( 12√2 )²
= 432 - 288
= 144
r = √(√(144))
= √12
= 2√3