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~ikan Q, Ph = 15.000 Pa
~p (rho /massa jenis air) = 1.000 kg/m³
~g = 10 m/s
Ditanya : selisih kedalaman ikan P dan Q
Jawab :
*cari ketinggian masing² ikan
a.) ikan P
Ph = p.g.h
6.000 Pa = 1.000 kg/m³. 10 m/s. h
h = 6000 / 1000 . 10
h = 6000 / 10.000
h = 0,6 m = 60 cm
b.) ikan Q
Ph = p.g.h
15000 = 1000. 10. h
h = 15.000 / 10.000
h = 1,5 m = 150 cm
*selisih
Q - P
150 cm - 60cm
= 90 cm ( B )
semoga bermanfaat :)