( 3x - 6 )° + ( 4x + 25 )° = 180°
7x° + 19° = 180°
7x° = 180° - 19°
x = 161° : 7°
x = 23°
pelurus∠boc = 3x - 6
= 3.23 - 6
= 69 - 6
= 63°
<AOC dan <BOC merupakan sudut berpelurus, dimana jumlah sudut adalah 180°
<AOC = (3x - 6)°
<BOC = (4x + 25)°
180° = <AOC + <BOC
180° = 3x - 6 + 4x + 25
180° = 7x + 19
7x = 180 - 19
7x = 161
x = 161 ÷ 7
<AOC = 3x - 6
= 3(23) - 6
by: Annafa
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( 3x - 6 )° + ( 4x + 25 )° = 180°
7x° + 19° = 180°
7x° = 180° - 19°
x = 161° : 7°
x = 23°
pelurus∠boc = 3x - 6
= 3.23 - 6
= 69 - 6
= 63°
<AOC dan <BOC merupakan sudut berpelurus, dimana jumlah sudut adalah 180°
<AOC = (3x - 6)°
<BOC = (4x + 25)°
180° = <AOC + <BOC
180° = 3x - 6 + 4x + 25
180° = 7x + 19
7x = 180 - 19
7x = 161
x = 161 ÷ 7
x = 23°
<AOC = 3x - 6
= 3(23) - 6
= 69 - 6
= 63°
by: Annafa