Question

tolong pake caraa yaa

Answer 1

pH larutan = 5 - log 0,7

Penjelasan:

Mol HCl

= M x V

= 0,1 x 10

= 1 mmol

Mol NH4OH

= 0,1 x 10

= 1 mmol

Persamaan Reaksi:

HCl + NH4OH ---> NH4Cl + H2O

1 mmol 1 mmol -

1 mmol 1 mmol 1 mmol

- - 1 mmol

asam kuat dan basa lemah habis bereaksi, maka pH garam nya adalah:

Molaritas garam NH4Cl

= mol/V total

= 1 mmol/20 ml

= 0,05 M

[H+]

= akar (Kw/Kb x M garam)

= akar 10^(-14)/10^(-5) x 0,05

= akar 0,05 x 10^(-9)

= akar 0,5 x 10^(-10)

= 0,7 x 10^(-5)

pH

= - log [H+]

= - log 0,7 x 10^(-5)

= - log 0,7 + 5

= 5 - log 0,7

Answer 2

Penjelasan:

mol HCl = 0,1 × 10 = 1mmol

mol NH4OH = 0,1 × 10 = 1mmol

HCl + NH4OH --> NH4Cl + H2O

m: 1mmol. 1mmol. –. –

b: -1mmol -1mmol. +1mmol

s:. –. –. 1mmol

M = n/v = 1/20

= 0,05

= 5.10^-2

[H+] = √kw/kb .mg

= √10^-14/10^-5 × 5.10^-2

= √10^-9 × 5.10^-2

= √5.10^-11

= 7.10^-6

pH = -log[H+]

= -log7.10^-6

= 6-log7

= 6-0,8

= 5,2

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