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Verified answer
CD / BC = EF / FGCD / 30 = 10 / 20
CD = 1/2 x 30
CD = 15 cm
AB / BC = AG / FG
AB / 30 = 22 / 20
AB = 22/20 x 30
AB = 33 cm
AD² = BC² - (AB - CD)²
= 30² - (33 - 15)²
= 30² - 18²
= 900 - 324
= 576
AD = √576
= 24 cm
Luas trapesium
= 1/2 x (AB + CD) x AD
= 1/2 x (33 + 15) x 24
= 1/2 x 48 x 24
= 576 cm²
Jawaban D
ABCD = I
AGFE = II
DC I / EF II = CB I/FG II
DC / 10 =30/20
20.DC = 10.30
DC = 300 / 20
DC = 15 cm
AB I/AG II =CB I / FG II
AB I/22 = 30/20
AB. 20 = 22.30
AB = 660 : 20
AB = 33
AD ² =BC² - (AB -CD) ²
AD² =30² - 18²
AD² = 900- 324
AD =√576
AD = 24
LUAS ABCD
(a + b) x t /2
(15+33) x 24 /2
48 x 12= 576cm²