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Verified answer
Kurva y = a^2 x^2 + ax + a berada di bawah kurva 2ax^2 - y + ax + 1 = 0=> y = 2ax^2 + ax + 1
a^2 x^2 + ax + a < 2ax^2 + ax + 1
a^2 x^2 - 2ax^2 + a - 1 < 0
(a^2 - 2a)x^2 + (a - 1) < 0 ====> definit negatif (a < 0 dan D < 0)
1) a^2 - 2a < 0
=> a (a - 2) < 0
=> a = 0 atau a = 2
Garis bilangan
+++ (0) --- (2) +++ => ambil daerah yg negatif
2) D < 0 => b^2 - 4ac < 0
=> 0^2 - 4(a^2 - 2a)(a - 1) < 0
=> -4a (a - 2)(a - 1) < 0
=> a = 0 atau a = 2 atau a = 1
Garis bilangan
+++ (0) --- (1) +++ (2) --- => ambil daerah yg negatif
Irisan kedua garis bilangan
1) ........... (0) xxxxxxxxxxxxxx (2) ..............
2) .......... (0) xxxxxxx (1) .......... (2) xxxxxxx
Daerah irisannya : 0 < a < 1