Tolong nomor 12^^ pake cara ya.... Question from @Shafaa32

May 2020 1 34 Report

Tolong nomor 12^^ pake cara ya

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Yang diketahui :
Jangkauan terjauh (X maks) = 40 m
Jangkauan tertinggi (Y maks) = 30 m

Yang ditanya sudut elevasi (a)

Pembahasan.

Persamaan jangkauan terjauh :

$xmaks = \frac{ {vo}^{2} \sin(2 \alpha ) }{g}$

Persamaan jangkauan tertinggi :

$ymaks = \frac{ {vo}^{2} {( \sin( \alpha )) }^{2} }{2g}$

Sehingga :

$40 = \frac{ {vo}^{2} \sin(2 \alpha ) }{10}$

$400 = {vo}^{2} \sin(2 \alpha )$

${vo}^{2} = \frac{400}{ \sin(2 \alpha ) }$
Pers (1)

$30 = \frac{ {vo}^{2} {( \sin( \alpha )) }^{2} }{2 \times 10}$
$600 = {vo}^{2} {( \sin( \alpha ) )}^{2}$

${vo}^{2} = \frac{600}{ { (\sin( \alpha ) )}^{2} }$
Pers 2.

Maka,

$\frac{400}{ \sin(2 \alpha ) } = \frac{600}{ {( \sin( \alpha ) )}^{2} }$

$\frac{ {( \sin( \alpha ) )}^{2} }{ \sin(2 \alpha ) } = \frac{600}{400}$

$\frac{ \sin( \alpha ) \sin( \alpha ) }{2 \sin( \alpha ) \cos( \alpha ) } = \frac{3}{2}$

$\frac{ \sin( \alpha ) }{ \cos(?) } = 3$

$\tan( \alpha ) = 3$
$\tan( \alpha ) = \tan(72)$
$\alpha = 72$

Kesimpulan.
Sudut elevasinya sekitar 72°

=====\\(^_^)//=====

Mapel : Fisika
Materi : Gerak Parabola

1 votes Thanks 1

Shafaa32 thankyou^^

yunus3022 sama"

Shafaa32 kak tolong kayanya rumus xmax nya salah deh.. kurang cos

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Tolong nomor 21 yaa pake cara

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Tolong nomor 21 yaa pake cara

Tolong please dikumpul besok​

Tolong please dikumpul besok​

Tolong please dikumpul besok​

Tolong please dikumpul besok​

Tolong dibantuu terimakasih ​

Tolong dibantu. terimakasih​

Tolong dibantu yaaaa​

Tolong dibantu ya..​

Tolong yaa please :)​

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Tolong please dikumpul besok

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Tolong dibantu yaaaa

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Tolong yaa please :)