Question

Tolong nomer 28 :')) plus cara yaa terimakasih

Answer 1

Limit (x -> 0)  ( x . cos 2x) / ( tanx - sin 2x)
jika x = 0 --> bentuk 0/.0

d'hospital

= ( 1 . cos 2x + x(-2 sin 2x)) / ( sec² x - 2 cos 2x)
jika x = 0
= ( 1. cos 0) - 0(-2). sin 0) / (sec² 0 - 2 cos 0)
= (1 - 0)/(1 - 2)
= 1/ -1
= - 1