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x = (12-6)/3
x = 2
17)
g(-2) = -2a + b = -4
g(-6) = -6a + b = 12
~~~~~~~~~~~~~~~~ -
4a = -16
a = -4
-2(-4) + b = -4
b = -8 - 4
b = -12
g(x) = -4x - 12
20) n(P) = 4
n(Q) = 3
banyaknya korespondensi satu² = 0
karena n(P) ≠ n(Q)