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makakoefisien muai volume besi = 3* 12 * 10^-6γ1 = 36 * 10^-6 /C
koefisien muai volume minyakγ2 = 950 * 10^-6 /C
Kenaikan suhu ΔT = 40 - 20 = 20 Cperubahan volume tong
ΔV1 = V * γ1 * ΔTΔV1 = 70 * 36*10^-6 * 20ΔV1 = 5.04×10⁻² = 0.0504 liter perubahan volume minyak
ΔV2 = V * γ2 * ΔTΔV2 = 70 * 950*10^-6 * 20ΔV2 = 1.33 liter
Volume minyak yg tumpah adalah
V = ΔV2 - ΔV1V = 1.33 - 0.0504V = 1.2796 liter
ΔV = 70 * (950*10⁻⁶ - 12*10⁻⁶) * (40 - 20)
ΔV = 1,3132 liter ≈ 1,3 liter
Jawaban C