Question

Tolong kerjain ya + pakai cara

Answer 1

Dengan pemfaktoran dan identifikasi akar:
x² - 4x + 3 = 0
(x-1)(x-3) = 0
Sehingga,
x₁ = 1
x₂ = 3
Maka, dengan komposisi akar demikian:
(x-1/x₁²)(x-1/x₂²) = 0
x² - (1/x₁² + 1/x₂²)x + 1/(x₁²x₂²) = 0
x² - (x₁²+x₂²)/(x₁²x₂²) x + 1/(x₁²x₂²) = 0
(x₁²x₂²)x² - (x₁²+x₂²)x + 1 = 0
(1²3²)x² - (1²+3²)x + 1 = 0
9x² - (1+9)x + 1 = 0
9x² - 10x +1 = 0 [E]