Question

Tolong kasih tau nomor 10 dan 12 pake cara ya makasih

Answer 1

Verified answer

10. cari sisi miring segitiga = √16² + 12² = √256 + 144 = √400 = 20 cm
       sisi miring segitiga = diameter lingkaran = 20 cm
       keliling lingkaran = phi x D
       keliling setengah lingkaran = 1/2 x phi x D = 1/2 x 3,14 x 20 = 31,4 cm
       keliling bangun tsb adalah = 31,4 + 12 + 16 = 59,4 (Jawabannya D)

12. Keliling lingkaran = 2 x phi x r = 2 x 22/7 x 7 = 44 cm
     panjang busur AB = ∠AOB/360 X Keliling
     5,5 = AOB/360 X 44
     5,5 / 44 = AOB/360
      1/8 = AOB/360
     AOB = 360 / 8
     AOB = 45° (Jawabannya B)

Answer 2

Verified answer

10. d^2 = 16^2 + 12^2
d^2 = 256 + 144
d^2 = 400
d = 20
keliling setengah lingkaran = 1/2 x phi x d =
= 1/2 x 3,14 x 20
= 3,14 x 10
= 31,4
Total keliling = 16 + 12 + 31,4
=59,4
12. d = 2r
= 2 x 7
= 14
k = phi x d
= 22/7 x 14
= 22 x 2
= 44
Besar sudut = 5,5/44 x 360
= 1/8 x 360
= 45°