Question

Tolong kasih “diketahui” dan “ditanya” kak

Terimakasih

Answer 1

Verified answer

Diketahui:

r = 18 cm

Kondisi a: di = 3do

Kondisi b: di = -3do

Ditanya: Jarak benda di depan cermin (do) = ???

Kondisi a.

f = 1/2 r

f = 1/2 (18 cm)

f = 9 cm

1/f = 1/do + 1/di

1/(9) = 1/do + 1/(3do)

1/(9) = 3/3do + 1/3do

1/9 = 4/ 3do

do = 12 cm

do = 12cm

Kondisi b.

1/f = 1/do + 1/di

1/ (-9) = 1/do - 1/3do

1/(-9) = 3/3do - 1/3do

1/(-9) = 2/3do

3do = -18

do = -6 cm

Answer 2

Jawaban:

Cermin Cekung

Penjelasan:

R = 18 cm

F = 1/2 R

= 9 cm

Ditanya:

a. Jarak benda (SO) jika nyata dan diperbesar 3x

b. Jarak benda (SO) jika maya dan diperbesar 3x

Jawaban

M = SI/SO

3 = SI/SO

3 SO = SI

a.

1/F = 1/SI + 1/SO

1/9 = 1/3SO + 1/SO

1/9 = 1/3SO + 3/3SO

1/9 = 4/3SO

SO = 1/9:4/3

SO = 1/9x3/4

SO = 3/36

SO = 36/3

SO = 12 cm

Ruang II : R<SO<F : 18<12<9

Sifat bayangan : Nyata, terbalik, diperbesar

b.

1/F = 1/SI + 1/SO

1/9 = 1/-3SO + 1/SO

1/9 = -1/3SO + 3/3SO

1/9 = 2/3SO

SO = 1/9:2/3

SO = 1/9x3/2

SO = 3/18

SO = 18/3

SO = 6 cm

Ruang I : SO<F : 6<9

Sifat bayangan : Maya, tegak, diperbesar

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