Question

Tolong kak fisika kls12

Answer 1

3.
R = 120 Ω
Q = 300 mC = 300×10⁻³C
t = 1 menit = 60 detik

cari dulu kuat arusnya
I = Q/t
I = 300×10⁻³ / 60
I = 5×10⁻³ A

lalu masukkan ke persamaan hukum ohm
V = I . R
V = 5×10⁻³ . 120
V = 600×10⁻³
V = 0,6 Volt

4.
I = 5 A
V = 12 V
t = per menit artinya 60 detik

besar muatan, Q = ...?

I = Q/t
5 = Q/60
Q = 5×60
Q = 300 C