Jawaban:
1. 2.500 J
2. 200 cm
3. 500 N
Penyelesaian:
1] m = 50 kg
v1 = 0 m/s
v2 = 10 m/s
W = ΔEk = ½m(v2²-v1²)
= ½ . 50 (10² - 0²)
= 25 (100)
= 2.500 Joule
2] KM = 2
R = 100 cm = 1m
KM = Jari-jari poros roda (r)/Jarak jari-jari roda (R)
2 = r/100
r = 200 cm = 2 m
3] m = 50 kg
g = 10 m/s²
W = m × g = 50 × 10 = 500 N
ΣF = 0
T - W = 0
Tambahkan kedua ruas dengan W
T - W + W = 0 + W
T = W = 500 N
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Jawaban:
1. 2.500 J
2. 200 cm
3. 500 N
Penyelesaian:
1] m = 50 kg
v1 = 0 m/s
v2 = 10 m/s
W = ΔEk = ½m(v2²-v1²)
= ½ . 50 (10² - 0²)
= 25 (100)
= 2.500 Joule
2] KM = 2
R = 100 cm = 1m
KM = Jari-jari poros roda (r)/Jarak jari-jari roda (R)
2 = r/100
r = 200 cm = 2 m
3] m = 50 kg
g = 10 m/s²
W = m × g = 50 × 10 = 500 N
ΣF = 0
T - W = 0
Tambahkan kedua ruas dengan W
T - W + W = 0 + W
T = W = 500 N