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f(x) = x³+3x²-24x+3
f'(x) = 3x² + 6x -24
f'(x) = 0
3x² + 6x - 24 = 0
(3x+12)(x-2) = 0
jadi 3x + 12 = 0
3x = - 12
x = -12/3 = -4
dan x - 2 = 0
x = 2
jadi titik stasionernya di (2,0) dan (-4,0)