Question

Tolong jwab no 13 dngn penjelasannya :)

Answer 1

Q = 14,4 π liter/s = 1,44 π * 10⁻² m³/s
P₁ = 80 kPa = 80.000 Pa
g = 10 m/s²
r₁ = 12 cm = 0,12 m
A₁ = πr₁² = π*(0,12)² = 0,0144 π m² =1,44 π * 10⁻² m²
r₂ = 6 cm = 0,06 m
A₂ = πr₁² = π*(0,06)² = 0,0036 π m² = 3,6 π * 10⁻³ m²

a) kecepatan aliran di pipa 1 dan pipa 2
v₁ = Q / A₁
v₁ = 1,44 π * 10⁻² / (1,44 π * 10⁻²) = 1 m/s

v₂ = Q / A₂
v₂ = 1,44 π * 10⁻² / (3,6 π * 10⁻³) = 4 m/s

b) Tekanan pada pipa 2
P₁ + ¹/₂ ρv₁² + ρgh₁ = P₂ + ¹/₂ ρv₂² + ρgh₂
80.000 + ¹/₂ * 1000 * 1² + 1000*10*0 = P₂ + ¹/₂ * 1000 * 4² + 1000 * 10 * 2
80.500 = P₂ + 28.000
P₂ = 52.500 Pa