Question

Tolong jwab meanteman
sebuah benda tinggi 2cm didrpan
lebsa cembung degan fokus 10cm
jika jarak benda ke lensa 5cm
maka jarak bayangan je lensa adalah

Answer 1

Jarak bayangan ke lensa nya -10

1/f = 1/si + 1/so
1/10 = 1/si + 1/5
1/10 - 1/5 = 1/si
1-2/10 = 1/si
-1 / 10 = 1/si
si = - 10

Answer 2

1/f = 1/s + 1/s' 1/10 = 1/5 + 1/s' 1/10-1/5=1/s' 1/10+2/10=1/s' 3/10=1/s' 3×s'=10 s'=10/3 = 3,33cm