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4) log (|y| + 12) ≥ 1
|y| + 12 ≥ 10
|y| ≥ -2
y² ≥ 4
(y + 2)(y - 2) ≥ 0
y ≤ -2 atau y ≥ 2
5) ((2x - 3)/(3x - 2)) = f(4x + 1)
utk x = 1 >> f(5) = (2 - 3)/(3 - 2) = -1