Question

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1.X²+y² = 52
x-y²=20
2.3x²+2y²=29
X-2y²=7

Answer 1

1. X²+y² = 52 ⇒ y²= 52-X²
x-y²=20
x-( 52-X²) = 20
x-52+X² =20
x-52+X² -20 = 0
X²+x-72 = 0
(x-8)(x+9) = 0
x=8 ; x=-9

2. 3x²+2y²=29 ⇒ 2y²= 29-3x²
x²-2y²=7
x²-(29-3x²) = 7
x²-29+3x²-7 = 0
4x²-36 = 0 (dibagi 4)
x²-9 =0
(x-3)(x+3) = 0
x=3 ; x=-3

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