annisatiarasuni
Perbandingan panjang : lebar = 2 : 1 keliling = 48 m ditanya = panjang tanah pak sudarmanto jawab •keliling = 48 m •2(p+l) = 48 m • p+l = (48 / 2) m • p+l = 24 m
maka p = • 2/(2+1) × 24 • 2/3 ×24 p = 16
jawaban = A
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hunaifatus
Diketahui= p= 2x = l = x =K= 48 Ditanya = p? Jawab= K =2(p+l) 48 =2 (2x+x) 48 =4x+2x 48 = 6x X= 48/6 =8
keliling = 48 m
ditanya = panjang tanah pak sudarmanto
jawab
•keliling = 48 m
•2(p+l) = 48 m
• p+l = (48 / 2) m
• p+l = 24 m
maka p =
• 2/(2+1) × 24
• 2/3 ×24
p = 16
jawaban = A
= l = x
=K= 48
Ditanya = p?
Jawab=
K =2(p+l)
48 =2 (2x+x)
48 =4x+2x
48 = 6x
X= 48/6 =8
P = 2x =2(8)=16 m