Question

Tolong jawabkan yaa...cuma 2 kokk...gk bnyak...
pleaseeee....ini sebentar lg dikumpull....

Answer 1

A) 3p + 2q = 1
3(1/(3 + √3) + 2(1/(2√3 + 2)) = 1
3(3 - √3)/(9 - 3) + 2(2√3 - 2)/(12 - 4) = 1
(1/2)(3 - √3) + (1/4)(2√3 - 2) = 1
(3/2) - (1/2)√3 + (1/2)√3 - 1/2 = 1
1 = 1 (terbukti)

b) p/q = (2/3)√3
(2√3 + 2)/(3 + √3) = (2/3)√3
(2√3 + 2)(3 - √3)/(9 - 3) = (2/3)√3
(6√3 - 6 + 6 - 2√3)/6 = (2/3)√3
4√3 / 6 = (2/3)√3
(2/3)√3 = (2/3)√3 (terbukti)