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ΔH = ∑ΔH°f produk - ∑ΔH°f reaktan
- 98,3 = [ 2 ΔH°f SO3] - [2 ΔH°f SO2 + ΔH°f O2]
- 98,3 = [2 ΔH°f SO3] - [(2 × - 296,8) + 0]
ΔH°f SO3 = - 345,95 kJ