r = 7 cm
[tex] \rm d_{2} = CD = 25 \: cm[/tex]
[tex] \rm panjang\: AB = \sqrt{{7}^{2}+{7}^{2}}\\= \sqrt{{49}+{49}}\\ = \sqrt{98} \\={7}\sqrt{2} \: cm\\ \rm a.\: AD = \sqrt{{25}^{2}-{7}^{2}}\\= \sqrt{{625}-{49}}\\= \sqrt{576}\\ = 24 \: cm[/tex]
[tex] \rm b. \: Luas\: Segitiga \:ACD \\= \frac{1}{2}\times {a} \times {t} \\= \frac{1}{2} \times {AD} \times {AC} \\= \frac{1}{2} \times {24} \times {7} \\= {12} \times {7} \\= {84} \: cm\\c.\: Luas \:Segiempat \:ACBD\\= \frac{{d}_{1} \times {d}_{2}}{2} \\=\frac{{AB}\times {CD}}{2}\\=\frac{{7}\sqrt{2}\times{25}}{2}\\=\frac {{175}\sqrt{2}}{2}\\={87,5}\sqrt{2}\: {cm}^{2}\\d.\:AE = \frac{AB}{2}\\=\frac{{7}\sqrt{2}}{2}\\={3,5}\sqrt{2}\:{cm}\\e. \:{AB}={7}\sqrt{2}\:{cm}[/tex]
[tex]\:[/tex]
[tex]\rm {By\: Answer \:AR.257.Hero}[/tex]
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Jawaban:
r = 7 cm
[tex] \rm d_{2} = CD = 25 \: cm[/tex]
[tex] \rm panjang\: AB = \sqrt{{7}^{2}+{7}^{2}}\\= \sqrt{{49}+{49}}\\ = \sqrt{98} \\={7}\sqrt{2} \: cm\\ \rm a.\: AD = \sqrt{{25}^{2}-{7}^{2}}\\= \sqrt{{625}-{49}}\\= \sqrt{576}\\ = 24 \: cm[/tex]
[tex] \rm b. \: Luas\: Segitiga \:ACD \\= \frac{1}{2}\times {a} \times {t} \\= \frac{1}{2} \times {AD} \times {AC} \\= \frac{1}{2} \times {24} \times {7} \\= {12} \times {7} \\= {84} \: cm\\c.\: Luas \:Segiempat \:ACBD\\= \frac{{d}_{1} \times {d}_{2}}{2} \\=\frac{{AB}\times {CD}}{2}\\=\frac{{7}\sqrt{2}\times{25}}{2}\\=\frac {{175}\sqrt{2}}{2}\\={87,5}\sqrt{2}\: {cm}^{2}\\d.\:AE = \frac{AB}{2}\\=\frac{{7}\sqrt{2}}{2}\\={3,5}\sqrt{2}\:{cm}\\e. \:{AB}={7}\sqrt{2}\:{cm}[/tex]
[tex]\:[/tex]
[tex]\rm {By\: Answer \:AR.257.Hero}[/tex]