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pola 2 = (1+2+3)
pola 3 = (1+2+3+4)
pola 10 = (1+2+3+....+11)= ((1+11)/2)x11 = 66
pola 100 = (1+2+3+....+101= ((1+101)/2)x101= 5.151
1+[n(n+3):2]