#F
(1) ΔBCP siku di C, BC= 8√2 dan CP = 1/2 (8) = 4 --> BP = √(BC)²+(CP)² = 12
(2)ΔAHQ siku di H, AH = 4√2, HQ = 3 --> AQ = √(AH²+ HQ²) = √41
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#F
(1) ΔBCP siku di C, BC= 8√2 dan CP = 1/2 (8) = 4 --> BP = √(BC)²+(CP)² = 12
(2)ΔAHQ siku di H, AH = 4√2, HQ = 3 --> AQ = √(AH²+ HQ²) = √41