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Verified answer
Jawab1.
(x² y² 2⁻³ ) / (3 x⁶ (-2y)⁻³ =
= (x² .y ². y³ (-2)³ / (2)³ . 3 x⁶
= - 8(x² y⁵)/(8)(3)(x⁶)
= -(y⁵)/(3x⁴)
2.
5(x² . y⁻³)⁴ / 3 (-x) =
= -5/3 (x⁸ y⁻¹²) / (x)
= - 5/3 (x⁷)/(y¹²)
= (-5 x⁷)/(3 y¹²)