Question

Tolong jawab no.2 ya
terimakasih :)

Answer 1

Verified answer

Program Linier

titik potong garis dengan sumbu x dan sumbu y
2x +y = 8
x=0, y = 8 --> A(0,8)
y = 0 , x = 4--> B(4,0)

x + 2y = 7
x = 0 , y = 7/2 --> C = (0, 7/2)
y = 0, x = 7 --> D(7, 0)

titk potong  dua garis
2x + y = 8
x + 2y  =7 ...kalikan 2
.
2x + y = 8
2x + 4y = 14
kurangkan
-3y = -6
y = 2 --> x + 2y = 7
x + 4 = 7
x = 3
titik potong E (3,2)
.
daerah tertutup  dengan titik pojok  untuk f(x,y) = 25 x +30 y
A(0,8) --> f(x,y)= 25(0) + 30(8) = 240
C(0, 7/2) --> f(x,y) = 25(0) + 30(7/2) = 105
E(3,2) ---> f(x,y) = 25(3) + 30(2) = 75 + 60 = 135
.
maksimum = 240
minimum = 105