Question

Tolong jawab ini pliiss

Answer 1

43)
P= panjang garis singgung dalam =3r
J= jarak dua pusat = 15 cm
R = r + r + 1 = (2r + 1)

J² = P² + R²
15² = 9r² + (2r+1)²
9r² + 4r² + 4r + 1 = 225
13r² + 4r - 224 = 0
(13 r + 56)(r - 4)= 0
r = 4

44)
Luas arsir = luas segitiga - luas juring
tan <COA = AB/OA
AB = OA . tan <COA
AB  =4 . tan 45
AB = 4
luas segitiga = OA x AB/2 = 4x4 /2 = 8

luas juring = 45/360 x π r² = 1/8 x π x 16 = 2π

luas arsiran = 8 - 2π