Question

Tolong jawab hari ini,(jwbn trbk)
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Jangan ngasal, harus pakai jalan, kalau bener, insya Allah nnti jadi jwbn terbaik

Answer 1

a.

11^(x² + 3x+ 2) = 121^(x² - 3x + 2)

11^(x² + 3x + 2) = 11^{2(x²-3x+2)}

x² + 3x + 2 = 2x² - 6x + 4

x² -2x² +3x + 6x + 2 - 4 = 0

- x² + 9x - 2 = 0

a = -1, b = 9 , c = - 2

x₁ + x₂  = -b/a = -(9)/(-1) = 9/1 = 9

x₁.x₂ = c/a = (-2)/(-1) = 2/1 =2

b.

5^(x²-3x+2) + 5^(x²-3x +1) = 30

5^(x²-3x).5^2 + 5^(x²-3x). 5^1 = 30

25. 5^(x²-3x) + 5 . 5^(x²-3x) = 30 .

(25+5) .5^(x²-3x) = 30

(30). 5^(x²-3x) =  30

5^(x²-3x) = 1 = 5^0

x²-3x = 0

a = 1 , b = -3 , c = 0

x₁+x₂ = -b/a = -(-3)/(1) = 3

x₁. x₂ = c/a = 0/1 = 0

3.

5^(x²+2x+5)= 5^(-3x-1)

x² + 2x + 5 = -3x -1

x² + 2x + 3x + 5 + 1= 0

x² + 5x + 6 = 0

a= 1, b = 5 , c = 6

x₁+x₂ = -b/a = -(5)/6 = -5/6

x₁.x₂ = c/a = 6/1 = 6

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