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(x,y)⇒ (r, α)
x = -4, y=4
(karena x negatif dan y positif, maka α sudut di kuadran II)
r =√ x^{2}=y^{2}
⇒√-4^{2}+4^{2}
⇒√32
⇒4√2
tan α = x/y
⇒4/ - 4
⇒ - 1
karena α sudut di kuadran II, maka : α = (180-45)°= 135°
maka koordinat kutubnya ialah ( 4√2, 135°)