Question

Tolong ini gimana caranya?

Answer 1

Jawab = B
3/(x+2)  - 6/(x-1)  > 0
[3(x-1) - 6(x+2)] / [(x+2)(x-1)] > 0
(3x-3 - 6x -12 )/(x+2)(x-1) > 0
(-3x -15)(x+2)(x-1) > 0
-3x-15 = 0 --> x = -5
x+2 = 0 --> x = -2
x-1 = 0 --> x = 1
uji dgn garis bilangan > 0

..(+)....(-5)..(-)....(-2)..(+).....(1).(-)..
x < - 5  atau -2 < x < 1