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Segitiga ABC , AB aku misalin c , BC aku misalin a , AC aku misalin b
BC² = AC² + AB² - 2AC×AB×Cos A
√6² = √2² + c² - 2×√2×c×Cos 60
6 = 2 + c² - 2×√2×c×
6 = 2 + c² - √2c
4 = c² - √2c
0 = c² - √2c - 4
trus di faktorkan ketemu
(c + √2) (c - 2√2)
c = -2 ∧ c = 2√2
karena ga mungkin panjang sisi berupa negativ jadi ketemu jawabanya
c = 2√2
(√6)² = (AB)² + (√2)² - 2 (AB) (√2) cos 60°
6 = (AB)² + 2 - 2 (AB) (√2)(1/2)
6 = (AB)² + 2 - AB√2
0 = (AB)² - AB√2 - 4
0 = (AB - 2√2) (AB + √2)
AB - 2√2 = 0
AB = 2√2cm (memenuhi)
AB + √2 = 0
AB = - √2 (tidak memenuhi)
jadi AB = 2√2cm