Question

Tolong dongg, nomor yang dilingkarin aja kok

Answer 1

1. misal y=f(x)
y=2x-6
x=y+6/2
jadi f invers (x) =x+6/2
=1/2x+6/2
=1/2x+3 (B)

2. misal y=f(x)
y=4x-1
x=y+1/4
f invers (x) = x+1/4
f invers (7) = 7+1/4 =8/4=2 (B)

3. f(x-3) =2x-4
misal y=f(x-3)
y=x-3
x=y+3
f(x) =2(x+3) -4
=2x+6-4
=2x+2
misal y=f(x)
y=2x+2
x=y-2/2
f invers (x) =x-2/2
=1/2x-2/2
=1/2x-1 (A)

4.misal y=2/x+3
xy+3y=2
y(x+3) =2
x+3= 2/y
x = 2/y -3 = 2-3y/y
f invers (x) = 2-3x/x (A)

5. caranya sama kayak nomor 4

7. misal y= ³√x-5 -8
y+8=³√x-5
(y+8)³=x-5
(y+8)³+5=x
f invers (x) = (x+8)³+5 (A)

8. misal y = (x+4)^5 -3
y+3=(x+4)^5
akar5√y+3 =x+4
akar5√y+3 -4 = x
f invers (x) = akar5√x+3 -4 (B)

9.saya tidak tahu


jadikan jawaban yg terbaik yak:),,