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F(x) = (3x - 600 + 60/x).(x)
= 3x^2 - 600x + 60
F'(x) = (3x^2 - 600x + 60) dx
= 6x - 600
Minimum / maksimum => f'(x) = 0
0 = 6x - 600
X = 100 jam