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Verified answer
L : x² + y² + 10x - 6y - 30 = 0pusat (-5, 3)
r² = 64
(-5, 3) dicerminkan terhadap garis y = -x sehingga bayangannya (-3, 5)
matriksnya
maka titik bayanganya
x = x' + 3
y = y' - 5
sehingga persamaan bayangan lingkarannya
(x + 3)² + (y - 5)² = 64
x² + y² + 6x - 10y + 9 + 25 - 64 = 0
x² + y² + 6x - 10y - 30 = 0
———> L = (-y)^2 + (-x)^2 + 10(-y) + 6(-x) - 30
L = y^2 + x^2 - 10y - 6x - 30
L = x^2 + y^2 - 6x - 10y - 30
Sayarat pencerminan y=-x
Variabel x diganti -y
Variabel y diganti -x
Maaf yaaa kalau salah, semoga membantu ^_^