Question

Tolong dong sama caranya yg no.5

Answer 1

(2,3)=(x1,y1)
(-2,1)=(x2,y2)

(y-y1)/(y2-y1) = (x-x1)/(x2-x1)
(y-3)/(1-3) = (x-2)/(-2-2)
(y-3)/(-2) = (x-2)/(-4)
(y-3)/1 = (x-2)/2
2y - 6 = x - 2
2y = x + 4
y = (1/2)x + 2 (B)