Question

Tolong dong penyelesaiannya harap dibantu Tuliskan persamaan garis melalui ( 3,-3)
a.tegak lurus garis y=2x+5
b.sejajar garis 2x+3y=-6
c.tegak lurus garis 2x+3y=-6

Answer 1

A) y-y1 = -1/m(x-x1)
   y -(-3) = -1/2(x-3)
   y +3 = -1/2 x + 3/2
     y = -1/2 x + 3/2 - 3  kalikan 2
    2y = -x + 3 - 6
   2y = -x -3
   x + 2y +3 = 0

b) y-y1 = m(x-x1)
     y +3 = -2/3(x-3)
     y = -2/3 x + 2 - 3
     y = -2/3 x -1 kalikan 3
    3y = -2x -3
    2x + 3y + 3 = 0

c) y-y1 = -1/m(x-x1)
    y+3 = 3/2(x-3)
    y+3 = 3/2 x - 3/2 kalikan 2
    2y = 3x - 3 - 6
    2y - 3x + 9 = 0