Question

Tolong dong pakai caranya. makasih

Answer 1

Verified answer

Kubus
• ABCD.EFGH

rusuk = x
sudut antara ADHE dan CE = a

Perhatikan ∆CDE
tan DEC = tan a
tan a
= CD/DE
= x /x√2
= 1/√2
= 1/2 √2

Answer 2

Verified answer

Jawab
rusuk kubus a = 2
DE = diagonal sisi = a√2
CD= rusuk = a
CE = diagonal ruang = a√3

sudut CE, ADHE= sudut <CED
Δ EDCsiku siku di D
tan <CED = CD/DE = a/a√2 = 1/√2 = 1/2 √2