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Verified answer
Kubus• ABCD.EFGH
rusuk = x
sudut antara ADHE dan CE = a
Perhatikan ∆CDE
tan DEC = tan a
tan a
= CD/DE
= x /x√2
= 1/√2
= 1/2 √2
Verified answer
Jawabrusuk kubus a = 2
DE = diagonal sisi = a√2
CD= rusuk = a
CE = diagonal ruang = a√3
sudut CE, ADHE= sudut <CED
Δ EDCsiku siku di D
tan <CED = CD/DE = a/a√2 = 1/√2 = 1/2 √2